Module 8: Rational Exponents and Rational Expressions

Topics

  1. Radicals and Radical Functions
  2. Rational Exponents
  3. Simplifying Radical Expressions
  4. Arithmetic Operations with Radical Expressions
  5. Rationalizing Denominators and Numerators of Radical Expressions
  6. Radical Equations and Problem Solving
  7. Complex Numbers

I. Radicals and Radical Functions

After completing this section, you should be able to:

A. Finding Square Roots

To find the square root of a number a, think of a number that when multiplied by itself will equal a. In other words, the square root of a is one of two equal factors of a. For example, one square root of 25 is 5 because:

5 · 5 = 52 = 25

Another square root of 25 is –5 because:

(–5) (–5) = (–5)2 = 25

We denote the nonnegative, or principal, square root with the radical sign:

square root sign with 25 under it

We denote the negative square root with a negative radical sign:

square root sign with 25 under it and negative sign in front of it

An expression containing a radical is called a radical expression. The expression under the radical sign is called a radicand.

radical expression of square root of a

Let's summarize these concepts.

Principal and Negative Square Roots

If a is a nonnegative number, then:

We have already seen that to find the square root of a number a, we think of a number that when multiplied by itself will equal a. But how do we find the square root of a variable raised to an exponent? It's easy if we remember that when we multiply, we add exponents. So to find the exponent of the square root, we only have to divide the variable's exponent in half.

Study the examples below (for simplicity, we assume all variables represent positive numbers):

square root of 10 = x10/2 = x5   Remember that x5 · x5 = x10.
square root of 8 = x8/2 = x4   Remember that x4 · x4 = x8.
square root of 22 = x22/2 = x11   Remember that x11 · x11 = x22.

Now try some examples yourself to become familiar with these ideas.

Example 1: Find the square roots.
(Assume all variables represent positive numbers.)
a.   square root of 36 Solution
b.   square root of 0 Solution
c.   square root of 4/49 Solution
d.   square root of .25 Solution
e.   square root of x to the 6th power Solution
f.   square root of 9x to the 12th Solution
g.   - square root of 81 Solution
h.   square root -81 Solution

B. Approximating Square Roots Using a Calculator

Numbers such as 1, 4, 9, 16, and 25 are called perfect squares because each is the square of a rational number. Therefore, square roots of perfect squares are equal to rational numbers.

The square root of a number that is not a perfect square, such as square root of 3, is not a rational number. It is an irrational number, and we can find its decimal approximation using a calculator. For example, square root of 3 is approximately equal to 1.732, as written below.

square root of 3 approx. equal 1.732

Example 2: Use a calculator to approximate  square root of 20 approx.. Round your answer to three decimal places. You can find an approximation for any square root by keying the number into the calculator and pushing the square-root button.
   
Solution: Using a calculator,  square root of 20 approx. equal 4.472

C. Finding Cube Roots

The method we use to find square roots can be extended to find higher-order roots, such as cube roots. The cube root of a number is one of the three equal factors of the number. For example, the cube root of 8 is 2 because:

2 · 2 · 2 = 23 = 8

We indicate the cube root as follows:

cube root of 8 = 2

Remember that when we found the square root of a variable raised to an exponent, we divided the exponent by 2. Now, to find the cube root of a variable raised to an exponent, we divide the exponent by 3. The examples below will help you understand this concept.

cube root of x to the third= x3/3 = x Remember that x1 · x1 · x1 = x3.
cube root of 20= x30/3 = x10 Remember that x10 · x10 · x10 = x30.
cube root of 1000x to the 12th = 10x12/3 = 10x4 Remember that 10x4 · 10x4 · 10x4 = 1,000x12.

 

Cube Roots

The cube root of a real number a is written cube root of a.

cube root of a = b only if b3 = a

Now practice finding cube roots to ensure you understand this concept.

Example 3: Find the cube roots.
  a.   cube root of 1 Solution
b.   cube root of -64 Solution
c.   cube root 8/125 Solution
d.   cube root x to the 6th Solution
e.   cube root of -27x to the 9 Solution

D. Finding nth Roots

We can extend our discussion of square roots and cube roots to include roots other than these two. The nth root of a number a, where n is a natural number greater than 1, is written:

radical sign with index n, radicand a

The number n is called the index, and is usually not shown when we indicate square roots, where n = 2.

We find the nth root of a number or a variable raised to an exponent in the same way we find square and cube roots. To find the nth root of a number, we find a number that when raised to the nth power, gives the original number. In other words, the nth root of a number is one of n equal factors of the number. In the case of a variable raised to an exponent, we divide the exponent by n.

For example (for simplicity, we assume all variables are positive):

5 square root of x to the 25th = x25/5 = x5 because  x5 · x5 · x5 · x5 · x5 = (x5)5 = x25
5 square root of 32 because  2 · 2 · 2 · 2 · 2 = (2)5 = 32
cube root of 8x to the 6th because  (–2x2)(–2x2)(–2x2) = (–2x2)3 = –8x6

Now try some examples yourself.

Example 4: Find the indicated roots.
  a.   square root -3 squared Solution
b.   square root of 25x squared Solution
c.   4 square root (x - 2) to the 4th Solution
d.   5 square root (x + 4) to the 5th Solution

E. Find n root to nth power, Where x is a Real Number

We will now look at the cases when the index of the radical is even, and there are variables in the radicand. If we restrict the variables to positive numbers, then the resulting root will be positive.

If the variables are negative numbers, however, we must use absolute-value bars to ensure that the result is a positive number. For example, we write:

absolute value formula

to ensure that the result is positive. The same situation occurs when the index is any even number. Note that when the index is an odd number, absolute-value bars are not necessary. Why?

Try to work out the solutions to the examples below, then look at how we found the answers.

Example 5: Find the roots. Variables may represent any real number.
  a. 
  b. 
  c. 
  d. 
   
Solution: a. 
  b. 
  c. 
  d. 

(Note that absolute-value bars are not needed in part d because the index is odd.)

F. Graphing Square- and Cube-Root Functions

The square-root and cube-root operations can be represented by the functions:

f(x) = square root of x and g(x) = cube root of x

We know that the square root of a negative number is not a real number. Therefore, the domain of the square-root function is the set of all nonnegative real numbers. The domain of the cube-root function, however, is the set of all real numbers because the index is odd.

Now look at the graphs of the two functions square root of x and cube root of x.

Example 6: Graph the square root function f(x) = square root of x.
   
Solution: We know that the domain is the set of all nonnegative real numbers. Therefore, we evaluate the function for several values of +x, plot the resulting points, and connect the points with a smooth curve.

Figure 8.1
Graph of f(x) =

f(x)= square root of x table Figure 5.1 graph

 

Example 7: Graph the function f(x) = cube root of x
Solution:

The domain of this function is the set of all real numbers. As before, we will evaluate the function for several values of x, both positive and negative. Then we plot the points and connect them with a smooth curve. Where needed, we will use a calculator to approximate values.

Figure 8.2
Graph of f(x) = cube root of x

Figure 5.2 Table f(x) = cube root

II. Rational Exponents

After completing this section, you should be able to:

A. Definition of a1/n

In this section, we will study expressions that have non-integer exponents, such as 31/2 or x2/3. We will define these expressions so that all the existing rules for exponents will also apply when the exponents are rational numbers.

Let's begin by looking at 51/3. Let:

x = 51/3

Then, by cubing both sides of this equation, we obtain:

x3 = (51/3)3
x
3 = 5

From this equation, we can deduce that x is the number whose cube is 5, or:

x = 3 cube root of 5

This equation leads us to conclude that 51/3 = 3 cube root of 5.

Definition of a1/n

If n is a positive integer greater than 1 and n root of a is a real number, then:

a1/n = n root of a

We can use this definition to solve the problems below.

Example 1: Use radical notation to write the following. Simplify, if possible.
a.   41/2 Solution
b.   641/3 Solution
c.   –91/2 Solution
d.   (81x8)1/4 Solution
e.   5y1/3 Solution

B. Definition of am/n

Next, we will expand the discussion of rational exponents to include exponents such as m over n. As before, we define the meaning of these exponents so that the rules for exponents still hold true.

Now look at the exponential expression 82/3 in two different ways.

Based on the above, we can see that it does not matter whether you:

  1. raise the base to a power first and then take the nth root

    or

  2. take the nth root first and then raise the base to a power

Definition of am/n

If m and n are positive integers greater than 1 with m over n in lowest terms, then

definition of a to the m/n power

as long as n square root of ais a real number.

Now let's apply this definition to the problems below. Try to work out the solutions yourself, then look at our answers.

Example 2: Use radical notation to write the following. Simplify, if possible.
  1. 43/2
  2. –163/4
  3. (–27)2/3
  4. (4x – 1)3/5
Solution:
  1. 4 to the 3/2 power
  2. -16 to the 3/4 power
  3. -27 to the 2/3 power
  4. 4x -1 to the 3/5 power

C. Definition of am/n

Finally, we will discuss the case when the rational exponent is negative.

Definition of am/n

If am/n is a nonzero real number,

a to the -m/n power = 1 over a to the m/n power

Study the examples below to see how we use this definition.

Example 3: Write each expression with a positive exponent and simplify.
  1. 16–3/4
  2. –27–2/3
Solution:    16 to the 3/4 power

    -27 to the -2/3 power

D. Simplifying Expressions with Rational Exponents

The rules for exponents that were developed in module 6 also apply when the exponents are rational numbers. Thus, we can use these rules when simplifying expressions that contain rational exponents. For the remainder of this module, we will assume that variables represent positive real numbers, so that we do not need to use absolute-value bars when simplifying even roots.

For your convenience, we summarize the exponent rules below.

We can apply these rules to examples using rational exponents. Try these examples yourself, and then look at our solutions below. Write the answers with all positive exponents.

Example 4:
  1. x1/3x1/2
  2.  
Solution:
  1.  
  2.  
  3.  

  

E. Using Rational Exponents to Simplify Radical Expressions

Some radical expressions are easier to simplify if we first change them to rational exponents. Then, use the properties of exponents to simplify the exponents, and finally, change the expression back to radical notation.

Let's see how to do this by simplifying  .

Original expression.
(x4)1/8 = x4/8 Changed to an exponential expression.
x1/2 Simplified the exponent by reducing the fraction.
 Changed back to radical notation.

Now try some of these examples yourself before looking at our solutions.

Example 5: Use rational exponents to simplify.
 
Solution:
Example 6: Use rational exponents to write as a single radical.
 
Solution:
  1.  

III. Simplifying Radical Expressions

After completing this section, you should be able to:

Because radicals can be written as exponential expressions with rational exponents, it follows that the rules for exponents also apply to radicals. In particular, we will look at the product rule and quotient rule.

A. Using the Product Rule for Radicals

To verify that the product rule for radicals is valid, study the following:

These two examples show that  , which leads to the following rule.

Product Rule for Radicals

If  and  are real numbers, then

Now try to apply this rule.

Example 1: Multiply.
 
a.           Solution
b.           Solution
   

The next example is a little more complicated, so we have worked out the solution for you.

   
  c.  

B. Using the Quotient Rule for Radicals

We will verify that the quotient rule for radicals is similar to the quotient rule for exponents. Study the two examples below.

These examples show that:

We can express these findings as the rule below.

Quotient Rule for Radicals

If  and  are real numbers, and  is not zero, then

Now try to apply this rule.

Example 2: Use the quotient rule to simplify.
 
   
a.   Solution
b.    Solution
   
The next example is a little more complicated, so we will work out the solution for you.
   
  c.   

C. Simplifying Radicals

We can use both the product and quotient rules to simplify a radical.

Study the following examples.

Now try some examples yourself.

Example 3: Simplify.
 
a.  Solution
b.  Solution

Notice that in each case, we simplified the radical so that there are no perfect nth powers in the radicand. For example, if we are simplifying a square root, we make sure that the radicand does not contain any perfect squares. In general, we say that a radicand of the form  is simplified when the radicand a contains no factors that are perfect nth powers (other than 1 or –1).

Study the examples below to be sure you understand this process.

Example 4: Use the quotient rule to simplify.
 
a.

IV. Arithmetic Operations with Radical Expressions

After completing this section, you should be able to:

A. Adding or Subtracting Radical Expressions

Previously, we learned that we can add or subtract like terms by using the distributive property. Similarly, we can use the distributive property to add or subtract like radicals. We begin by defining like radicals as radicals with the same index and the same radicand. Let's look at the following examples to discover the rule for adding and subtracting like radicals.

From these examples, it can be seen that adding or subtracting like radicals is simply a matter of adding or subtracting the coefficients of the like radicals.

Try to do these examples yourself, then look at our solutions.

Example 1: Simplify. Assume that variables represent positive real numbers.
   
 
Solution:
a.   Problem.
     Factored under the radical so that one of the factors is a perfect cube.
     Wrote perfect cubes in exponential form.
     Simplified by taking perfect cubes out from under the radical.
     Multiplied 2 times 5.
     Combined like terms.
   
b. 

B. Multiplying Radical Expressions

To multiply radical expressions, we can use many of the same properties that were used to multiply polynomial expressions. For example, we can use the distributive property in the problem below.

We can also use the formula for the square of a binomial or the FOIL method to multiply binomials that contain radicals. Study the examples below to be sure you understand this process.

Example 2: Multiply.
a.    Problem.
                Applied FOIL method.
                Multiplied.
   
b.    Problem.
                =  Expanded form.
                =  Multiplied binomials.
                =  Multiplied.
                =  Simplified.

V. Rationalizing Denominators and Numerators of Radical Expressions

After completing this section, you should be able to:

A. Rationalizing Denominators that Have One Term

In this section, we look at division of radical expressions. When we divide radical expressions such as  , we usually want to write the result either without a radical in the denominator or without a radical in the numerator. The process of writing this expression without a radical in the denominator is called rationalizing the denominator because the denominator in the expression will only contain rational expressions.

To rationalize the denominator of square root of 3 over the square root of 2, we use the fundamental principle of fractions and multiply both the numerator and the denominator bysquare root of 2.

Try the examples below yourself, then look at our solutions.

Example 1: Rationalize the denominator of each expression.
  a. 
b. 
c. 
   
Solution: a. 
b. 
c. 

B. Rationalizing Dominators that Have Two Terms

When the denominator of a radical expression contains two terms, we must use a different method to rationalize the denominator. Recall that if we multiply the sum and difference of two radicals, the result does not contain any radicals.

Note that in this example, there are no radical signs in the answer because the two middle terms added to zero, as they always do when the sum and difference of two identical terms are multiplied. This observation will be useful when rationalizing the denominators of radical expressions.

We call  and  conjugates of each other. The example below shows how we can use conjugates to rationalize the denominator.

Now study the examples below to become familiar with this process.

Example 2: Rationalize each denominator.
 
 
 

C. Rationalizing Numerators

We now look at the process of rationalizing the numerator. This process is similar to that of rationalizing the denominator.

Example 3: Rationalize the numerator.
   
 

 

VI. Radical Equations and Problem Solving

After completing this section, you should be able to:

A. Solving Equations that Contain Radical Expressions

In this section, we look at methods for solving equations containing radical expressions. We will use the power rule to solve these equations.

Power Rule

If both sides of an equation are raised to the same power, all solutions of the original equation are among the solutions of the new equation.

Notice that this property states that the solutions of the new equation may not be solutions of the original equation. Therefore, each solution of the new equation must be checked to make sure it is also a solution of the original equation. If a proposed solution is not a solution of the original equation, it is called an extraneous solution.

Study the example below to see how to solve a radical equation.

Example 1: Solve
   
Solution: Use the power rule to square both sides of the equation.

Check this solution in the original equation.

Therefore, the solution set is {42}.

We summarize this process below.

Solving a Radical Equation

Step 1: Isolate one radical on one side of the equation.
Step 2: Raise each side of the equation to a power equal to the index of the radical and simplify.
Step 3: If the equation still contains a radical term, repeat Steps 1 and 2. If not, solve the equation.
Step 4: Check all proposed solutions in the original equation.

Now let's apply this process to a more difficult problem.

Example 2: Solve
   
Solution: First, isolate the radical term by subtracting 5 from each side of the equation.

Next, raise both sides to the third power to eliminate the radical.

Now we must check the solution by substituting –9 for x in our original equation, which was  .

                 Original equation.
                 Substituted –9 for x.
                 Simplified under the radical sign.
–2 + 5 = 3                 Took cube root of –8.
   3 = 3   True.      Compared.

The solution checks in the original equation, therefore, the solution set is {–9}.

   
Example 3: Solve
   
Solution:  

     x =    or   x – 3 = 0      Set each factor equal to 0.
                      x = 3

There are two solutions to this equation, and we must check both.

Check x = 0:     

Check x = 3:    

The solution 0 does not check, so 0 is an extraneous solution.
Therefore, the solution set is {3}.

   
Example 4: Solve
   
Solution: First, isolate one radical. It is best to isolate the more complicated one.

Next, square both sides and do the multiplication.

Now, isolate the remaining radical by following the steps above.

    Added –9 – 2x
                    Collected like terms.
               Switched sides.
           36(2x) = 16    Squared both sides.
               72x = 16    Multiplied 36(2x)
                      Divided by 72.

The proposed solution checks in the original equation, so the solution set is 2 over 9.

B. Using the Pythagorean Theorem to Model Problems

First, refresh your memory about the Pythagorean theorem.

Pythagorean Theorem

If a and b are the lengths of the legs of a right triangle, and c is the length of the hypotenuse, then a2 + b2 + c2.

Pythagorean Theorem

Now let's see how we use this theorem. First, we'll practice just using the theorem, then we'll apply it to a real-world problem.

Example 5: Find the length of the unknown leg of the right triangle whose hypotenuse is 10 meters and one of whose legs is 4 meters.

Figure 8.3
Pythagorean Theorem Example 5 Diagram

Example of Pythagorean Theorem

Solution: We use the Pythagorean theorem, with a = 4, and c = 10.

Because b represents the length of one leg of a right triangle, b cannot be negative. Why? Therefore, the unknown leg of the triangle is + 2 square root of 21 meters.

   
Example 6: A 50-foot supporting wire is to be attached to a vertical 75-foot antenna. Because of surrounding buildings, sidewalks and roadways, the wire must be anchored exactly 20 feet from the base of the antenna.

Figure 8.4
Pythagorean Theorem Example 6 Diagram

Tower is shown 75 feet high. A triangle is shown whose hypotenuse is 50 feet, whose base is 20 feet and whose height is x feet.

How high from the base of the antenna is the wire attached?

   
Solution: From the diagram, we can see that a right triangle is formed with a hypotenuse of 50 feet and one leg of 20 feet. Let x represent the other leg—the height from the base of the antenna to the attached wire.

Let a = 20, c = 50, and b = x, the required height.

We will use only the positive value,  , because x represents a length. Thus, the wire is attached exactly  feet from the base of the pole, or approximately 45.8 feet.

VII. Complex Numbers

After completing this section, you should be able to:

A. Imaginary and Complex Numbers

Earlier in this module, we saw that the square root of a negative number is not a real number. For example,  is not a real number because no real number exists whose square is –16.

In this section, we discuss a number system that includes roots of negative numbers. This number system is called the complex number system, and it includes the set of real numbers as a subset. The complex number system allows us to solve equations such as x2 + 1 = 0 that have no real-number solutions. To begin our study of the complex number system, we define the imaginary unit i.

Imaginary Unit

The imaginary unit, written as i, is the number whose square is –1. That is,

Using this definition, we can write the square root of a negative number in terms of i. For example,

Let's practice using the i notation.

Example 1: Express in terms of i.
 Solution
 Solution
 Solution

Now that we have defined imaginary numbers, we can define complex numbers.

Complex Numbers

A complex number is a number that can be written in the form a + bi, where a and b are real numbers.

Notice that the set of real numbers is a subset of the complex numbers because any real number can be written in the form a + 0i—a complex number.

a + bi is a real number when b = 0. A complex number is called a pure imaginary number if a = 0.

The following diagram shows the relationship between complex numbers and their subsets.

Figure 8.5
Hierarchy of Numbers
Hierarchy of Numbers

Adding or Subtracting Complex Numbers

Complex numbers can be added or subtracted by adding or subtracting their real parts, and then adding or subtracting their imaginary parts.

Let's look at the rules for these operations.

Sum or Difference of Complex Numbers

If a + bi and c + di are complex numbers, then:

(a + bi) + (c + di) = (a + c) + (b + d)i

(a + bi) – (c + di) = a + bi c di = (a c) + (b d)i

Now apply these rules to the examples below, then look at our solutions.

Example 2: Add or subtract. Write the result in the form a + bi.
  1. (2 + 3i) + (–3 + 2i)

  2. (–3 – 7i) –(1 – i)

Solution:
  1. (2 + 3i) + (–3 + 2i) = (2 –3) + (3 + 2)i = –1 + 5i

  2. (–3 – 7i) –(1 – i) = –3 – 7i –1 + i = –4 – 6i

C. Multiplying Complex Numbers

We can use the distributive property to multiply complex numbers in the same way we have used it previously. Also, we multiply two complex numbers the same way we multiply two binomials—by using the FOIL method or the rules for special products. Then, we use the relationship i2 = –1 to complete the multiplication process.

Work out the examples below, then look at our solutions.

Example 3: Multiply. Write the result in the form a + bi.
  1. 3i(2 – i)
  2. (2 – 5i)(4 + i)
  3. (2 – i)2
  4. (7 + 3i)(7 – 3i)
Solution:
  1. 3i(2 – i) = 6i – 3i2 = 6i –3(–1) = 6i + 3 = 3 + 6i

  2. (2 – 5i)(4 + i) = 8 + 2i – 20i – 5i2 = 8 – 18i + 5 = 13 – 18i

  3. (2 – i)2 = 22 + 2(2)(–i) + i2 = 4 – 4i – 1 = 3 – 4i
    Note that here we used the "square of a binomial" formula, discussed in module 6.

  4. (7 + 3i)(7 – 3i) = 72 – (3i)2 = 49 – 9i2 = 49 + 9 = 58
    Note that here we used the "product of the difference of two terms" formula, discussed in module 6.

D. Dividing Complex Numbers

Notice that in the last example (part d of example 3), the result is a real number. The complex numbers 7 + 3i and 7 – 3i are complex conjugates of one another. When complex conjugates are multiplied, the result is always a real number. A general rule for complex conjugates is given below.

Complex Conjugates

The complex numbers (a + bi) and (a bi) are called complex conjugates of each other, and:

(a + bi)(a bi) = a2 + b2

We will use complex conjugates to divide the complex numbers in the examples below. Study these examples to be sure you understand the process.

Example 4: Divide. Write the result in the form a + bi.
   
  a.  
   
  b.  

E. Raising i to Higher Powers

Finally, let's examine what happens when we raise the imaginary unit i to an exponent greater than 2. Observe the pattern below.

i2 = –1
i3 = i2 · i = (–1) · i = –i
i4 = i2 · i2 = (–1) · (–1) = 1
i5 = i4 · i = (1) · i = i
i6 = i4 · i2 = (1) · (–1) = –1
i7 = i4 · i3 = (1) · –i = –i
i8 = i4 · i4 = (1) · (1) = 1
i9 = i4 · i4 · i = (1) · (1) · i = i

Notice that this pattern repeats every 4th power. Thus, to find higher powers of i, we use the fact that i4 = 1, and rewrite the power of i in terms of i4.

Study the following example.

i22 = i20 · i2
= i4· i4 · i4 · i4 · i4 · i2
= (i4)5 · i2
= (1) · (1) · (1) · (1) · (1) · (–1)
= –1

Now try two examples for yourself. Solving the problems below will help you become familiar with the concept of imaginary numbers.

Example 5: Evaluate.
 
1.   i16 Solution
2.   i21 Solution

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